Math, asked by jannuanup24, 1 month ago

In the ∆DEF, MN||EF, DM=5cm, ME=10 cm, DF=18cm, the value of NF is

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Answers

Answered by BrainlyGovind

25

The value of NF is 13 cm

hope it helps you ☺️

Answered by abhishek022006

1

Answer:

value of NF is 13 cm.

Step-by-step explanation:

ATQ,

NF=DF-DN

=18-5=13

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