Question

In the diagram, ΔABC is similar to ΔDEC. AB = 10 cm, BC = (x + 2y) cm, AC = (3x – 4y) cm, CD = 4 cm, CE = 3 cm, and DE = 5 cm. The values of x and y is ____. *​

Answer 1

Answer:-

By property of similar triangle, we have

$\frac{AB}{DE} = \frac{BC }{DC} = \frac{AC}{CE}$

$\frac{4}{3} = \frac{BC }{4.8} = \frac{AC}{4.2}$

⇒ BC=6.4 and AC=5.6

Hence CA=5.6cm,DA=6.4cm