In the diagram, ABCD is a square with a side length of 10 cm. If AY = CX = 8 cm, the area of the
shaded region is
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Answer:
20 sq. cm
Step-by-step explanation:
Given,
Side of the square = 10 cm
So, Area of the square = ( 10 x 10 ) sq. cm
= 100 sq. cm
Now,
Triangle AYB and Triangle CXD are Right Angled Triangle.
Area of Triangle AYB = Area of Triangle CXD
Ar(AYB) = 1/2 x AY x AB
= 1/2 x 8 x 10
= 1/2 x 80
Ar(AYB)= 40 sq. cm = Ar(CXD)
Therefore, Area of Shaded Figure = Area of Square - Ar(AYB) - Ar(CXD)
Area of Shaded Figure = ( 100 - 40 - 40 ) sq. cm
= ( 100 - 80 ) sq. cm
Area of Shaded Figure = 20 sq. cm
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