Question

In the diagram AQB is parallel to CRD and PQRS is a straight line. Find the value of x​. Please answer the question to help me

Answer 1

In the above attachment,

( 2x-40 )° + ( 3x-10 )° = 180°

[ Interior angles same side of the transversal ]

• 5x - 50 = 180°
• 5x = 180 + 50
• x = 230/5
• x = 46

Therefore, the value of x is 46

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