Question

In the diagram below, all the measurements are given correct to the nearest cm. Calculate the greatest possible area of the shaded region.

Answer 1

${ \tt{ \huge{ \underline{ \underline{ \red{QUESTION }}}}}}$




▪ Calculate the greatest possible area of the shaded region??



${ \tt{ \huge{ \underline{ \underline{ \red{SOLUTION }}}}}}$




${ \dagger{ \purple{ \bold{ \: \: \: GIVEN }}}}$



${ \underline{ \pink{ \sf{dimension \: of \: outer \: rectangle}}}}$



${ \sf{ \blue{ = 42cm \: \times \: 21 \: cm}}}$



${ \underline{ \sf{ \pink{dimension \: of \: inner \: rectangle}}}}$



${ \blue{ \sf{ = 28cm \: \times \: 15cm}}}$



${ \dagger{ \purple{ \bold{ \: \: \: TO \: FIND }}}}$




${ \sf{ \rightarrow{greatest \: possible \: area }}} \\ { \sf{ \: \: \: \: \: \: of \: shaded \: region}}$



${ \underline{ \boxed{\green{ \sf{area \: of \: rectangle = length \times breadth}}}}}$




${ \star{ \sf{ \purple{ \: \: area \: of \: outer \: rectangle}}}} \\ \\ { \sf{ = 42cm \times 21cm}} \\ \\ { \sf{ = 882 {cm}^{2} }}$



${ \star{ \sf{ \purple{ \: \: \: area \: of \: inner \: rectangle}}}} \\ \\ { \sf{ = 28cm \times 15cm}} \\ \\ { \sf{ = 420 {cm}^{2} }}$




${ \red{ \sf{ \rightarrow{area \: of \: shaded \: region}}}} \\ \\ { \sf{ \blue{ = (area \: of \: outer \: rectangle}}} \\ { \sf{ \blue{ - area \: of \: inner \: rectangle)}}}$



${ \sf{ = 882 {cm}^{2} - 420 {cm}^{2} }} \\ \\ { \sf{ = 462 {cm}^{2} }}$



${ \boxed{ \pink{ \sf{area \: of \: shaded \: region = 462 {cm}^{2} }}}}$

Answer 2

Answer:

HEY

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