Question

In the diagram below find speed at T=6 seconds
PLZ SHOW STEPS TOO

Answer 1

Answer:

87.18 m/s

Explanation:

$u_{x }= 100*cos (30^{0})\\u_{x} = 50\sqrt{3}$  and $u_{y} = 100*sin(30^{0})\\u_{y} = 50$

Here, $v_{x}$ is constant but $v_{y}$ is not .

So, $v_{y} = u_{y} - gt$

 => $v_{y} = 50 - 10*6 = -10.$

Therefore, velocity =  $v=\sqrt{v_{x}^{2}+v_{y}^2}$

                                       = $\sqrt{7500+100}$  

                                       = 87.18 m/s.

Answer 2

Explanation:

Answer:

87.18 m/s

Explanation:

$$\begin{lgathered}u_{x }= 100*cos (30^{0})\\u_{x} = 50\sqrt{3}\end{lgathered}$$ and $$\begin{lgathered}u_{y} = 100*sin(30^{0})\\u_{y} = 50\end{lgathered}$$

Here, $$v_{x}$$ is constant but $$v_{y}$$ is not .

So, $$v_{y} = u_{y} - gt$$

=> $$v_{y} = 50 - 10*6 = -10.$$

Therefore, velocity = $$v=\sqrt{v_{x}^{2}+v_{y}^2}$$

= $$\sqrt{7500+100}$$

= 87.18 m/s.