Question

In the diagram below O id circumscribed about quadrilateral ABCD. What is the value of x?

Answer 1

tex]\int_{0}^{1} \frac{tan^{-1}x\:dx}{(1+x^{2})^{\frac{3}{2}}}=\frac{1}{\sqrt{2}}\lgroup\frac{\pi}{4}+1)\lgroup-1[/tex]Find : $\mathrm{\int \frac{(x+1)dx}{x(1+xe^{x})^{2}}dx}$

Answer 2

Answer:

Option C is correct.

Step-by-step explanation:

Given:

m∠B = 5x

m∠D = 75°

To find: Value of x

Since, Quadrilateral is inscribed in circle with center o.

⇒ ABCD is cyclic Quadrilateral.

We know that Sum of opposite angles of the cyclic quadrilateral is 180°.

So,

∠B + ∠D = 180°

5x + 75 = 180

5x = 180 - 75

5x = 105

x = 21

Therefore, Option C is correct.