Question

In the diagram below the area of the small piston is 2m2 and the large piston is 120 m2. a. If the small piston is pushed down with a force of 20N, calculate the pressure exerted on the liquid. b. If the same pressure is transmitted by the liquid to act on the large piston, calculate the force acting on the large piston

Answer 1

Answer:

By Pascal's law, the pressure increased using one piston is communicated everywhere in the fluid. Thus, the same pressure acts on the other piston.

Cross-sectional area of piston 1 is A

1

=100 cm

2

=0.01 m

2

Force on piston 1 is F

1

=10

7

dyne=100 N

Force on piston 2 is F

2

=2000 kg wt=2000×10=2×10

4

N

Let the cross-sectional area of Piston 2 be A

2

=A.

By Pascal's law, P

1

=P

2

⇒

A

1

F

1

=

A

2

F

2

⇒A

2

=

F

1

F

2

A

1

⇒A=

100

2×10

4

×0.01

=2 m

2

=2×10

4

cm

2

Answer 2

Answer:

Explanation:

this is the answer

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