Question

In the diagram given alongside, the potential difference across PR is 14 volts.

Calculate.

(a) the equivalent resistance of the network.

(b) the current flowing through PQ,

(c) the potential difference across PQ,

(d) the current flowing through the 3 ohms resistor.​

Answer 1

Answer:

Explanation:

I) Rs = 5ohms

1/Rp = 1/3 + 1/6 = 2+1/6 = 1/2

Rp = 2ohms

the equivalent resistance of the network = 7 ohms.

II) I = V/R

I= 14/2 => I = 2A

III) V= IR => V= 2×7= 14V

IV) Current through the 3ohm resistor =

6/9 × 2= 4/ 3A

HOPE THIS HELPS MY MATE!!!

Answer 2

Answer:

(a) Equivalent Resistance of QR =

1/Rp = 1/3+1/6

Rp = 3 ohm

In series arrangement

current remains same

and potential difference varies

Re = 5 +6 ohm

= 14 ohm

V = 14 V

V = I R

I = 2 A

(b) current flowing through PQ = 2 A

(c) potential difference across PQ = 2 × 5

= 10 V