In the diagram given below, a tangential force of 2 kg wt is applied round the circumference of the flywheel with the help of a string and mass arrangement. Now, if the radius of the wheel is 0.1 m, find the acceleration of the mass. Assume that the moment of inertia of a solid fly wheel about its axis is 0.1 kg m⁻².
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Let us assume linear acceleration =a
mass=m kg
Tension=T
mg- T=ma-----------(i)
Angular acceleration=α
couple acting will be :
Iα=TR----(II)
a=Rα--------------III
from equation i,ii and III
Mg-Iα R=mRα
α=mgR/(I+mR)²
Given that
mass= 2kg
R=0.1m
I=0.1kgm²
α=2x9.8x0.1/(0.1 +2x0.1)² rad /s²
=21.7rad/ s²
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