In the diagram given below angleEDC. The tangent drawn to the circle at C
makes an angle of 50° with AB produced. Find the measure of angleACB.
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Answered by
5
Answer:
50
Step-by-step explanation:
asmighanshani:
how ??
look the angle AGC is given to be 50 ok, so now we consider the triangle AGC
we know that the tangent always makes an angle of 90 to the surface so angle ACG is 90 hence angle CAG will be 180-90-50=40
is the diameter and the diameter always subtends an angle of 90 at the surface of the circle hence in triangle ABC the value of angle ABC=90
now consider triangle ABC the angle ACB=180-angle ABC-angle CAG =180-90-40=50
understood?
yes.!! thank you so much
;-)
Answered by
6
Answer:
angle ACB = 50
Step-by-step explanation:
AGC = 50 (given)
take AC as the diameter
then ACG = 90 (point of contact btw tangent and radius is 90)
in triangle ACG
180 - (90+50) = angle CAG
therefore CAG = 40
in triangle ABC
angle ABC = 90 (angle in a semi-circle is 90)
180-(90+40)=angle ACB
therefore angle ACB = 50
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