Question

 In the diagram given below EDC. The tangent drawn to the circle at C makes an angle of 50° with AB produced. Find the measure of ACB.

Answer 1

angle AGE=50

Consider AC diameter

In ∆ACG

angle ACG=90

=>angle CAG=40

In ∆ACB

angle CAB=40

=>angle ACB=50

Answer 2

Answer: Angle ABC = 50°

Answer: Angle ABC = 50°Step-by-step explanation:

Answer: Angle ABC = 50°Step-by-step explanation:Consider AC to be the circle's diameter, angle ECD = 50°

1. Answer: Angle ABC = 50°Step-by-step explanation:Consider AC to be the circle's diameter, angle ECD = 50°In the circle and the tangent, angle ACG =90° (as a tangent makes 90° with the circle's diameter
2. Answer: Angle ABC = 50°Step-by-step explanation:Consider AC to be the circle's diameter, angle ECD = 50°In the circle and the tangent, angle ACG =90° (as a tangent makes 90° with the circle's diameterIn ∆ACG, angle CAG = 180° - (angle ACG + angle ECD) = 180° - (90° + 50°) = 180° - 140° = 40°
3. Answer: Angle ABC = 50°Step-by-step explanation:Consider AC to be the circle's diameter, angle ECD = 50°In the circle and the tangent, angle ACG =90° (as a tangent makes 90° with the circle's diameterIn ∆ACG, angle CAG = 180° - (angle ACG + angle ECD) = 180° - (90° + 50°) = 180° - 140° = 40°Angle ABC = 90° (angle in semi-circle is 90°)
4. Answer: Angle ABC = 50°Step-by-step explanation:Consider AC to be the circle's diameter, angle ECD = 50°In the circle and the tangent, angle ACG =90° (as a tangent makes 90° with the circle's diameterIn ∆ACG, angle CAG = 180° - (angle ACG + angle ECD) = 180° - (90° + 50°) = 180° - 140° = 40°Angle ABC = 90° (angle in semi-circle is 90°)Angle ACB = 180° - ( angle ABC + angle CAB) = 180° - (40° + 90°) = 180° - 130° = 50°

Answer: Angle ABC = 50°Step-by-step explanation:Consider AC to be the circle's diameter, angle ECD = 50°In the circle and the tangent, angle ACG =90° (as a tangent makes 90° with the circle's diameterIn ∆ACG, angle CAG = 180° - (angle ACG + angle ECD) = 180° - (90° + 50°) = 180° - 140° = 40°Angle ABC = 90° (angle in semi-circle is 90°)Angle ACB = 180° - ( angle ABC + angle CAB) = 180° - (40° + 90°) = 180° - 130° = 50°Therefore, angle ACB = 50°

Answer: Angle ABC = 50°Step-by-step explanation:Consider AC to be the circle's diameter, angle ECD = 50°In the circle and the tangent, angle ACG =90° (as a tangent makes 90° with the circle's diameterIn ∆ACG, angle CAG = 180° - (angle ACG + angle ECD) = 180° - (90° + 50°) = 180° - 140° = 40°Angle ABC = 90° (angle in semi-circle is 90°)Angle ACB = 180° - ( angle ABC + angle CAB) = 180° - (40° + 90°) = 180° - 130° = 50°Therefore, angle ACB = 50°PLEASE MARK IT AS THE BRAINLIEST !!!