Question

In the diffraction pattern due to a single slit of width α at the first minimum is observed at the angle 30 degree when light of wavelength 5000a is incident on the clicked the first secondary maximum is observed at an angle of​

Answer 1

Q}___?

=> sin^-1 [ 3/ 4 ]

Explanation:

As the first minimum is observed at the angle of 30° in a diffraction pattern due to a single slit of width a.

i.e n = 1, = 30°

According to Bragg's law of diffraction,

=> a sinѲ = n λ

=> a sin 30° = ( 1 ) λ ...[n = 1 ]

=> a = 2 λ _[i] ... { ∵ sin 30° = 1/2 }

For Ist secondary maxima

=> a sinѲ1 = 3λ / 2

=> sinѲ1 = 3λ / 2a _[ii]

Substitute value of a from Eq [i] and Eq [ii] we get,

=> sinѲ1 = 3 λ/ 4λ

=> sinѲ1 = 3/4

=> Ѳ1 = sin^-1 [ 3/4 ]

Answer 2

Answer:

$\pink \theta1 = sin ^{? - 1} (3 \div 4)$

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