Physics, asked by Awantika9088, 1 year ago

In the diffraction pattern of single slit under bichromatic illumination, the first minimum with the wavelength lambda1 is found to be coincident with the third maximum at lambda 2.So
a- 3lambda1=0.3lambda2
b-3lambda1=lambda2
c-lambda1=3.5lambda2
d-0.3lambda1=3lambda2

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Answered by Anonymous
6
c.........................
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