Question

in the district.
6.
A cooperative society of fisherman implemented such an improved plan for the production
of fishes that the production in a year will be increased 10% in comparison to its previous
year. In the present year if the cooperative society can produce 406 quintals of fishes, let us
write by calculating, what will be the production of fishes after 3 years.​

Answer 1

Given :-

• In the present year if the cooperative society can produce = 406 quintals of fishes .
• The production in a year will be increased 10% in comparison to its previous year.

To Find :-

• what will be the production of fishes after 3 years. ?

Solution :-

we know that,

• Final value = initial value * [ 1 + (Rate of increasing/100) ]^(time period)

given that,

• Initial value of Production of fishes = 406 quintals.
• Rate of increasing per year = 10% .
• Time = 3 years.

so,

→ Production of fishes after 3 years = 406[1 + (10/100)]³

→ Production of fishes after 3 years = 406[1 + (1/10)]³

→ Production of fishes after 3 years = 406(11/10)³

→ Production of fishes after 3 years = (406 * 1331)/1000 = 540.38 qunitals (Ans.)

Hence, Production of fishes after 3 years will be 540.38 quintals.

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