Chemistry, asked by s1889ramanuj6347, 2 months ago

In the double displacement reaction between Aqueous potassium iodine and aqueous Lead Nitrate yellow precipitate of lead iodide is formed while performing the activity of Lead Nitrate is not available which of the following can be used in place Lead Nitrate ?

a) lead sulphate (insoluble)
b) lead acetate
c) Ammonium Nitrate
d) Potassium Sulphate ​

Answers

Answered by srajveer90051
0

Explanation:

Answer

Correct option is

B

Lead acetate

2KI(aq)+Pb(NO

3

)

2

(aq)→PbI

2

(s)+2KNO

3

In the above double displacement reaction, potassium Iodide(KI) and lead nitrate (Pb(NO

3

)

2

) dissociate in their aqueous states to form ions. The lead (Pb

2+

) ions combine with the iodide (I

) ions to form precipitates of lead iodide (PbI

2

). If Lead sulphate is used in place of lead nitrate, no precipitates of lead iodide will be formed, because lead sulphate being insoluble in water does not give Pb

2+

ions which can combine with I

to form PbI

2

. On the other hand, lead acetate dissociates in aqueous state to give Pb

2+

ions and CH

3

COO

ions . Therefore potassium iodide combines with lead acetate to form precipitates of lead iodide and potassium acetate.

2KI(aq)+Pb(CH

3

COO)

2

(aq)→PbI

2

(s)+2CH

3

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