Question

In the double displacement reaction between aqueous potassium iodide and aqueous lead nitrate, a yellow precipitate is formed is of : 1. KNO3 2. PbNO3 3. Pbl2 4. KI​

Answer 1

Answer:

PbNO3

Explanation:

Correct option is

B

Lead acetate

2KI(aq)+Pb(NO

3

)

2

(aq)→PbI

2

(s)+2KNO

3

In the above double displacement reaction, potassium Iodide(KI) and lead nitrate (Pb(NO 3)2

dissociate in their aqueous states to form ions. The lead (Pb 2+) ions combine with the iodide (I)

ions to form precipitates of lead iodide (PPbI2)