Question

in the effective resistance of three resistors 3ohms,5ohms,and R ohms connected in series is 14ohms the value of R is​

Answer 1

Answer:

Given: A resistance of 3Ω is connected in series with another resistance of 5Ω. A potential difference of 6V is applied across the combination.

To find the current through the circuit and potential difference across the 3Ω resistance.

Solution:

as the resistance are connected in series

so R=R

1

+R

2

=3+5=8Ω

now according to Ohm's law,

R=IR

⟹I=

R

V

⟹I=

8

6

⟹I=0.75A

So, 0.75A of current flow through circuit.

Now , Potential Difference across the 3Ω resistance is

V

1

=IR

1

⟹V

1

=0.75×3

⟹V

1

=2.25V

Now the corresponding current will be,

I

1

=

R

1

V

1

⟹I

1

=

3

2.25

⟹I

1

=0.75A=I