Question

IN THE ELECTRICAL CIRCUIT SHOWN THE POTENTIAL DIFFERENCE ACROSS THE 4 ohm resistor is ​

Answer 1

Answer:

The answer will be 4V.

Explanation:

So, we have given,

               Potential difference in the first(in sequence) resistor = 2V;

                 Resistence  of the first(in sequence) resistor = 2ohm;

               Resistence of the second(in sequence) resistor = 4ohm;

Now, the current will be constant in this circuit since it has resistors in sequence. Therefore current or I in each resistor will be same.

Hence, resistence of R1 (that we consider 1st in sequence) = V / R;

                     Here, V = potential difference across the resistor.

                                R = Resistence of the resistor.

Now, put the value in the formula;

                                    I = V / R =   2 / 2;

                                I = 1 A.

Now, I or current in R1 (that we consider 1st in sequence) = 1A.

So,  I or current in R2 (that we consider 2nd in sequence) = 1A.

                       Now, we have;

                           I = 1A ;

                           R1 (that we consider 1st in sequence) = 2 ohm;

                           R2 (that we consider 2nd in sequence) = 4 ohm;

Now, in order to get potential difference in resistor 2 (that we consider in the sequence), we have to use ohm's law i.e,

                            V = IR;

So, put the value in it;

                             V = (1)(4);

                                = 4V;

Yes, we got our answer and the answer is 4V.

That's all.