Question

in the electrolisis of water name the gas collected at anode and cathode, I what is the volume of gas collected at one electrode double than the other, what would happen if dilute h2so4 is not added to water

Answer 1

When electric current is passed through water , it decomposes to give hydrogen gas and oxygen gas.

                 ELECTRICITY

2H₂O(I) -----------------------> 2H₂(g) + O₂(g)

At cathode :

H+ ions will gain electrons and form Hydrogen gas 

2H⁺ +2e--->H2 (g)

At anode : Oxygen gas will be released 

4 OH⁻(aq)→O2(g) + 2 H2O(l) + 4 e−

II) The volume of hydrogen gas collected at cathode is more than volume of oxygen gas at anode because water is made up of 2 parts of hydrogen and 1 part of oxygen by volume.

iii) If dil.H2SO4 is added to water then the rate of electrolysis increases.

Answer 2

Answer:

In electrolysis of water :

a ) . Hydrogen gas collected at cathode. And oxygen gas gas collect at anode.

b ) . We know that in water there is 2 hydrogen atom and 1 oxygen atom. That's why volume of gas collected at one electrode double than the other.

c ) . Pure water is a bad conductor of electricity when we add drops of dil sulphuric acid we make it a good conductor of electricity.