Question

In the electrolysis of water, a) Name the gas collected at anode and cathode b) Why is the volume of gas collected at one electrode double than the other? c) What would happen if dil H2SO4 is not added to water?

Answer 1

in the electrolysis of water
(a) the gas is collected at cathode is Hydrogen , H₂
And the gas collected at anode is oxygen ,O₂

(b) first of all we should we reaction between Hydrogen and oxygen to form water :- 2H₂ + O₂ ⇔ 2H₂O
you can see that, 2moles of H₂ and 1 mole of O₂ react to form 2moles of H₂O
we can also say that , if we break 2moles of water (using electrolysis ) , we gain 2hole of H₂ and one mole of O₂
Here, P, T, are constant ,
So, Volume is directly proportional to number of moles
∴ if we break 2V of water, we get 2V of H₂ and 1V of O₂ .
That's why the volume is collected at one electrode is double than other .

(iii) A pure water is not good conductor of Electricity . when dil H₂SO₄ is not added then electrolysis of pure water can't be possible .

Answer 2

Answer:

In electrolysis of water :

a ) . Hydrogen gas collected at cathode. And oxygen gas gas collect at anode.

b ) . We know that in water there is 2 hydrogen atom and 1 oxygen atom. That's why volume of gas collected at one electrode double than the other.

c ) . Pure water is a bad conductor of electricity when we add drops of dil sulphuric acid we make it a good conductor of electricity.