Question

 In the equation 3x = 4 - x, tranposing (-x) to LHS, we get :- *


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Answer 1

Given:

↬equation 3x = 4 - x

To Find:

value of x

Analysis:

here we use: $\sf{\blue{\underbrace{transportation \: method}}}$

Solution:

$: ⟹ \sf3x  = 4 - x \\ \\ : ⟹ \sf3x + x = 4 \: \\ \\ : ⟹ \sf4x = 4 \: \: \: \: \: \: \: \: \: \\ \\ : ⟹ \sf \: x = \cancel \frac{4}{4} \: \: \: \: \: \: \: \: \: \: \\ \\ : ⟹ \sf \: x = 1\: \: \: \: \: \: \: \: \: \: \:$

$\blue{ \underline{ \boxed{ \pink{ \mathfrak{ \therefore \:value \: of \: x = 1}}}}}$

Verification:

now we put 1 in the place of the x and check weather it satisfies the rule.!

$: ⟹ \sf3 {\blue{ \: x }}= 4 - \blue{x}\: \: \: \: \: \: \: \: \: \\ \\ : ⟹ \sf 3( \blue{1}) = 4 - 3( \blue{1}) \\ \\ : ⟹ \sf3 = 3\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

L.H.S = R.H.S

$\blue{ \underline{ \sf{ \huge{ hence \: proved}}}} { \huge{\blue{\dag}}}$

hope this helps.!!