in the equation 4x+y=3; 5x-4y=5,find the type of solution
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Answer:
linear equation in two variable
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Solution
Given:-
- 4x + y = 3_____(1)
- 5x - 4y = 5_______(2)
Find :-
- Value of x & y
Explanation
Using Elimination Method
Multiply by 5 in equ (1) & 4 in equ(2)
- 20x + 5y = 15________(3)
- 20x - 16y = 20________(4)
Sub. equ(3) & equ(4)
==> 5y + 16y = 15 - 20
==> 21y = -5
==> y = -5/21
Keep Value of y in equ(3)
==> 20x + 5×(-5/21) = 15
==> 20x = 15 + 25/21
==> 20x = (15×21+25)/21
==> 20x = (315+25)/21
==> 20x = 340/21
==>x = 340/(21×20)
==> x = 17/21
Hence
- Value od x = 17/21
- Value of y = -5/21
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