In the equation C8 H18 + O2 --> CO2 + H2 O , how many units of oxygen are there on the right side of the equation?
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Answer:
On the L.H.S Carbon ----> 8
Hydrogen ------> 18
Oxygen --------> 2
On the R.H.S Carbon ---------> 1
Oxygen --------- 3
Hydrogen ---------> 2
Explanation:
The Balanced equation is
2(C8H18) + 25(O2) → 16(CO2) + 18(H2O)
I put the brackets so that it is easy to understand
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