In the equation F=G times m_(1)m_(2)/d^(2) F is
Answers
Answer:
Yes, it's true that the greater the distance between two objects with mass, the less gravitational force each will exert on the other. It gets a little more complicated in some cases - I'm thinking of the variation of the - but that's the general rule.
I'm assuming that by "explain W=mg ", you're asking what the implications of this varying force are on weight. The answer is that weight varies with distance too.
How is this possible? Well, take a look at this formula:
g(r)=−GM(r)r2
It's an approximation (you can find more info about its assumptions ) for gravitational acceleration due to a spherical body such as Earth. Notice that g varies with distance r ... and since W is a function of g , it must vary as well!
You might have been told that g≈9.8m/s , but this is really just the value at the Earth's surface. If you get significantly closer or further away from Earth, you'll find it varies.
Edit: The question originally read "the greater the distance, the more force will act...". Original answer below:
I think you've misread the equation! Let me format it a little more nicely:
F=Gm1m2d2
We can see that as d increases, so does the bottom of the fraction, so the total force F decreases... for the same reason that 12>14 !
Answer:
FORMULA =
g(r) = -GM(r)/(r)^2......
apply it ....
then find your answer....
by yourself.....