Question

In the equation for getting ammonia identify numerical values of stoichiometric coefficients-A,B & C:A moles of nitrogen + B moles of hydrogen----> C moles of ammonia​

Answer 1

Explanation:

y 2 units of copper (II) sulfate ( CuSO4 ) we have, we need to have 4 units of potassium iodide ( KI ). For every two dozen copper (II) sulfates, we need 4 dozen potassium iodides. Because the unit "mole" is also a counting unit, we can interpret this equation in terms of moles, as well: For every two moles of copper (II) sulfate, we need 4 moles potassium iodide.

The production of ammonia (NH3) from nitrogen and hydrogen gases is an important industrial reaction called the Haber process, after German chemist Fritz Haber.

N2(g)+3H2(g)→2NH3(g)(8.2.2)

The balanced equation can be analyzed in several ways, as shown in the figure below

Answer 2

Answer:

Given reaction for the formation of ammonia-

N2+3H2⟶2NH3

From the above reacton,

1 mole of N2 reacts with 3 moles of H2.

Therefore,

6 moles of N2 will react with 18 moles of H2.

Given amount of H2=6 moles

Therefore, H2 is the limiting reagent.

Therefore,

Again from the above reaction.

No. of moles of ammonia formed when 3 moles of H2 react with excess of N2=2

∴ No. of moles of ammonia formed when 6 moles of H2 react with excess of N2=32×6=4 moles

Hence 4 moles of ammonia are formed when 6 moles of N2 react with 6 moles of H2.