Question

in the equation of path of projectile
what is 'x'​

Answer 1

Answer:hope understood

Explanation:Quantity Value

Equation of path of projectile motion y = (tan θ0)x – gx2/2(v0cosθ0)2

Time of maximum height tm = v0 sinθ0 /g

Time of flight 2tm = 2(v0 sinθ0/g)

Maximum height of projectile hm = (v0 sinθ0)2/2g

Answer 2

Explanation:

simply,x is the horizontal velocity of the projectile

hope it helps you