Physics, asked by yashingole, 11 months ago

In the equation(P+a/V^2)(V-b)= constant, the unit of
a is
(a) dyne x cm^5
(c) dyne x cm^4
(b) dyne x cm^3
(d) dyne x cm^2
I
.​

Answers

Answered by rajsingh24
5

Answer:

hey mate your answer is....

Explanation:

option d) dyne x cm^4...........

Answered by Anonymous
7

Hey buddy ❤️❤️

Answer:

❤️❤️

For the unit of ‘a' -

By, taking the terms (P + a/v^2) from the equation,

Unit of ‘P' (Pressure) = Unit of ‘a' / Unit of ‘V^2' (Volume) (CGS System)

Unit of ‘a' = Unit of (P×V^2)

= (g - cm^-1 - s^-2)× (cm^3)^2

= g - cm^-1 - cm^6 - s^-2

= g - cm^5 - s^-2

= (g - cm - s^-2) × cm^4

Because, g-cm-s^-2 = Dyne

So,

Unit of ‘a' = Dyne × cm^4.........●

Hope it helps you ✌️✌️❤️❤️

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