In the equation, SO2+ YO2 - ZSOy, X, Y and z are
a) 2,1,2
b) 1,2,3
c) 2,3,1
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Answer:
S+O
2
→SO
2
ΔH=−298.2 kJ/mole
SO
2
+
2
1
O
2
→SO
3
ΔH=−98.7 kJ/mole
SO
3
+H
2
O→H
2
SO
4
ΔH=−130.2 kJ/mole
H
2
+
2
1
O
2
→H
2
OΔH=−287.3 kJ/mole
The formation of H
2
SO
4
H
2
+S+2O
2
→H
2
SO
4
can be calculated by adding the above four equations
ΔH=−(298.2+98.7+130.2+287.3)=−814.4 kJ/mole
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