In the equation x = dt + bt acceleration of the object is (x = displacement) :
(A) b/2
(B) b
(C) 2b
(D) none of these
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GIVEN THAT THE DISTANCE EQUATION X=dt + bt
differentiating both side we have
V= dx/dt= d+ b
differentiating again we get the value for acceleration
a = dv/dt = 0
hence we don't get any acceleration
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