In the equation x2 + px - 18 = 0, one of the roots is 6 and p is a constant. What is the value of p?
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If one root of x^2+px+12=0 is 4, and the equation x^2+px+q=0 has equal roots then the value of q is
a) 49/4
b) 4/49
c) 4
d) 1/4
e) 12
a) 49/4
b) 4/49
c) 4
d) 1/4
e) 12
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Answer:
6^2 + 6p - 18 = 0
36 + 6p - 18 = 0
6p + 18 = 0
6p = -18
p = -3
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