Question

in the equationax^2+bx+c=0,it is given that D=(b^2-4ac)greater than 0, then the roots of the equation are​

Answer 1

Answer:

$\mathbf{\color{purple}{\huge{✮}}}\mathbf{\blue{\huge{A}}}\mathbf{\color{aqua}{\huge{N}}}\mathbf{\green{\huge{S}}}\mathbf{\color{yellow}{\huge{W}}}\mathbf{\orange{\huge{E}}}\mathbf{\red{\huge{R}}}\mathbf{\color{maroon}{\huge{✮}}}$

In the equation ax2+bx+c=0, it is given that D=(b2-4ac)>0. Then, the roots of the equation are. Solution : When D>0,the roots of the given quadratic equation are real and unequal.

$\huge{\underline{\boxed{\purple{{★ Hence \: Verified ★}}}}}$

Answer 2

Answer:

real and distinct

Step-by-step explanation:

as D is greater than zero it shows

real and distinct root

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