In the equilateral triangle ABC, AD and BE are the medians on the sides BC and CA respectively.
Show that AD = BE.
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Answered by
22
by the prop of triangle opposite sides are equal therefore,AD=AB
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Answered by
100
AC = BC {Sides of an Equilateral Triangle}
E and D is the mid point of AC and BC
{ BE and AD are median }
So, CE = EA = CD = BD
Now, In Triangle ABE and Triangle ABD
AC = BD (Mention Above)
/_A= /_B (60°)
AB = AB (Common)
So, Triangle ABE congurent to Triangle ABD.
( by S.A.S criteria)
Therefore,BE = AD ( by CPCT )
HOPE IT HELPS YOU,
PLEASE MARK AS ☆BRAINLIEST ANSWER☆
E and D is the mid point of AC and BC
{ BE and AD are median }
So, CE = EA = CD = BD
Now, In Triangle ABE and Triangle ABD
AC = BD (Mention Above)
/_A= /_B (60°)
AB = AB (Common)
So, Triangle ABE congurent to Triangle ABD.
( by S.A.S criteria)
Therefore,BE = AD ( by CPCT )
HOPE IT HELPS YOU,
PLEASE MARK AS ☆BRAINLIEST ANSWER☆
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