Question

in the equilateral triangle ABC is a triangle where p is the any point of BC if BP is equal to 1 by 4 BC then prove that 13 is equal to 16 a p square

Answer 1

I let 'D' as any point on BC,

ΔABC, BD= (¼) BC

AB = BC = CA = a (say)

Hence DC = (3/4) BC = 3a/4

Draw AE ⊥ BC ⇒ BE = EC = (1/2) BC=a/2

Since ABC is equilateral triangle, Hence DE = BE – BD In DAED, by Pythagoras theorem we have

16AD²= 13BC²

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