In the event of an accidental decomposition, a solution of rare H2SO4 was taken and electricity was passed through it?
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Electrolysis of dilute sulphuric acid:-
At cathode-
2H
+
+2e
−
⟶H
2
At anode-
4OH
−
+⟶2H
2
O+2O
2
+4e
−
Overall reaction-
H
2
O⟶2H
2
+O
2
∴ Amount of substance liberated at cathode = 2 moles of H2
=4g
Also, amount of substance liberated at anode = 1 mole of O2
=32g
∴ Ratio of the amount of substance liberated at the cathode and anode = 4
Explanation:
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