Question

In the experiment on finding the weight of a given body by the parallelogram law of vector, a student observes that he can find the unknown weight by using two equal weights of 100 g each makes an angle 90 degree. The unknown weight is likely to have a value of (nearly) :

a)100 g wt

b)141 g wt

c)500 g wt

d)102 g wt​

Answer 1

Answer:

b

Explanation:

you can understand this answer

Answer 2

Given:

Two equal weights of 100 g each

Angle between vectors=90

To find:

The unknown weight (resultant vector)

Solution:

A vector has both magnitude and direction.

Vectors are added using parallelogram law.

Sum of two vectors A and B with angle β between them =

         $\sqrt{A^{2} + B^{2} +2ABcos\beta }$

Here, angle β=90°

Unkown weight = $\sqrt{100^{2}+100^{2}+20000cos90 }$

= 100$\sqrt{2}$

= 100X1.41

=141g wt

The unknown weight is likely to have a value of b)141 g wt.