in the expression 3n-10 substitute 1,2,3,4 and 5 for n and write the values of the expression in order state with reason why the sequence obtained in an A.P.
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Hey mate!!
Here's ur answer:
=> 3n-10
= 3(1)-10. = 3-10. = -7
3(2) -10 = 6-10. = -4
3(3)-10. = 9-10. = -1
3(4)-10. = 12-10. = 2
3(5)-10. = 15-10. = 5
The sequence formed is:
-7,-4,-1,2,5
d= a2 -a1
= -4 -(-7)
= -4+7
= +3
d = a3- a2
= -1 -(-4)
= -1+4
=+3
So, the common difference 'd' is same i.e. +3
So it is an A.P.
Hope u understand
Mark me as the BRAINLIEST
Here's ur answer:
=> 3n-10
= 3(1)-10. = 3-10. = -7
3(2) -10 = 6-10. = -4
3(3)-10. = 9-10. = -1
3(4)-10. = 12-10. = 2
3(5)-10. = 15-10. = 5
The sequence formed is:
-7,-4,-1,2,5
d= a2 -a1
= -4 -(-7)
= -4+7
= +3
d = a3- a2
= -1 -(-4)
= -1+4
=+3
So, the common difference 'd' is same i.e. +3
So it is an A.P.
Hope u understand
Mark me as the BRAINLIEST
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