in the expression 3n-10,substitute values 1,2,3,4 and 5 for n and write the values of the expression in order state , with reason , whether the sequence obtained is an A.P.
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= 3(1)-10. = 3-10. = -7
3(2) -10 = 6-10. = -4
3(3)-10. = 9-10. = -1
3(4)-10. = 12-10. = 2
3(5)-10. = 15-10. = 5
The sequence formed is:
-7,-4,-1,2,5
d= a2 -a1
= -4 -(-7)
= -4+7
= -3
d = a3- a2
= -1 -(-4)
= -1+4
=-3
the common difference 'd' is i.e. -3
So it is an A.P.
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