Question

In the expression 3n-10, substitute values 1,2,3,4, and 5 for n and write the values of expression in order. State, with reason, whether the sequence obtained is an A. P.

Answer 1

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Answer 2

Answer:

=> 3n-10

    3(n1)-10. = 3-10. = -7

    3(n2) -10 = 6-10. = -4

    3(n3)-10. = 9-10. = -1

    3(n4)-10. = 12-10. = 2

    3(n5)-10. = 15-10. = 5

    The sequence formed is: -7,-4,-1,2,5

    d= a2 -a1        d = a3- a2

    = -4 -(-7)             = -1 -(-4)

    = -4+7                 = -1+4

    = +3                    = +3

    So, the common difference 'd' is same i.e. +3

    So it is an A.P.

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