In the factorization of 3x^2-20x-192=0, how can -20x be split into two terms?
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Step-by-step explanation:
-20x should be split into 2 two terms in such a way that their product = -192×3x²= -576x² = -36x×16x
so, -36x+16x =20x
3x²-36x+16x-192=0
3x(x-12)+16(x-12)=0
(3x+16)(x-12)=0
3x+16=0, x-12=0
x=-16/3,12
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