In the fig. 4.40,AD is of <BAC, if AB=10cm, AC=14cm and BC=6cm.Find BD and DC.
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BD=2.5CM , CD=3.5CM
Step-by-step explanation:
in ΔABC
AD bisect ∠BAC
BD/CD=AB/AC
⇒x/6-x=5/14=5/7
7x=30-5x
x=30/12=5/2
x=2.5cm
BD=2.5CM
CD=3.5CM
hope it helps you
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Hey Buddy here's ur answer.
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