Question

In the fig 6:41 AB parallel DE angle =35 degree and Angel CDF =53 degree find angle DCE

Answer 1

Please first give the figure

Answer 2

Hello mate ☺

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Solution:

It is given that AB∥DE. Therefore, ∠BAC=∠DEC              (Alternate Interior Angles)

∠BAC=35°      (Given)

Therefore, ∠DEC=35°

In ∆DCE, we have

∠DEC+∠CDE+∠DCE=180°         (Sum of three angles of a triangle =180°)

⇒35°+53°+∠DCE=180°

⇒∠DCE=180°−35°−53°=92°

I hope, this will help you.☺

Thank you______❤

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