Question

in the fig AB=10, find AC&BC​

Answer 1

Answer: sinC=AB/AC

then

sin30°=AB/10

sin30°=1/2. then

1/2=AB/10

AB=10/5

AB=5

similarly

cosC=BC/AC

cos30°=BC/10

cos30°=√3/2

(√3/2)×10=BC

BC=5√3

Answer 2

Step-by-step explanation:

In ΔCAE

CF/CE = CD/AC

CD/AC = 2.5/6 = 25/60

⇒ CD/AC = 5/12 ------ 1)

Let CF = 5x and CE = 12x

In ΔCAB,

CE/BC = CD/AC

CD/AC = 6/BC ------ 2)

From equation (1) and equation (2)

6/BC = 5/12

⇒ BC = (12 × 6)/5

⇒ BC = 72/5

⇒ BC = 14.4