In the fig, AB = 12 cm, BC = 8 cm and AC = 10 cm, find AD+BE+CF.
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Answer:
15
Step-by-step explanation:
Let BE = x. Hence, BD = x and CE = CF = 8-x and AD = AF = 12-x.
AF + FC = AC = 10, i.e 12-x+8-x=10
hence, x = 5.
Therefore, AD = 7, BE = 5, CF = 3.
Hence, AD + BE + CF = 15
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