Question

In the fig,ab||cd and a transversal l cuts ab and cd at a and c respectively. Bisected of angle a and angle c intersect at each other at p . Prove that angle apc =90 degree

Answer 1

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here's your answer!!☺☺

ANGLE BAC+ANGLE DCA=180(CO-INTERIOR ANGLES)
(ANGLE BAC+ANGLE DCA)÷2=180÷2(THINGS WHICH ARE HALVES OF THE SAME THINGS ARE EQUAL TO ONE ANOTHER)
THEREFORE HALVE ANGLE BAC+HALVE ANGLE DCA=90
ANGLE ACP+ANGLE CAP=90(AP AND CP ARE ANGLE BISECTORS)
ANGLE ACP+ANGLE CAP+ANGLE P = 180(SUM OF ALL ANGLES OF TRIANGLE)
90+ANGLE P=180(ANGLE ACP+ANGLE CAP=90 DEGREES)
ANGLE P=180-90
ANGLE P=90 DEGREES
HENCE PROVED
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