in the fig ab cd and ef concurrent at o find the value of y
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adeshmwardhe72:
u are from which grade
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angle COE= angle FOD(vertically opposite angle)
SO angleFOD=2y.
AOB is straight line.
so angle (BOF+FOD+DOA)=180°
or,5y+2y+2y=180°
or,9y = 180°
or,y = 180°/9
therefore y= 20 °
SO THE VALUE OF y is 20°.(Ans)
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SO angleFOD=2y.
AOB is straight line.
so angle (BOF+FOD+DOA)=180°
or,5y+2y+2y=180°
or,9y = 180°
or,y = 180°/9
therefore y= 20 °
SO THE VALUE OF y is 20°.(Ans)
If you like it Mark as brainliest
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