Math, asked by Baiahunlang, 21 days ago

in the fig., AB||CD. Find the value of x​

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Answers

Answered by Jha28utkarsh
2

Answer:

20°

Step-by-step explanation:

<EGH = 85° (Corresponding Angle)

<MGH = 180° - 85° = 95° (Linear Pair)

x + 95° = 115° ( Exterior Angle Property)

x = 20°

Answered by yashitav181
1

Answer:

20°

Step-by-step explanation:

  • EGH=85°(corresponding angles)

  • EGH=85°(corresponding angles)MGH+EGH= 180°(Linear pair)

EGH=85°(corresponding angles)MGH+EGH= 180°(Linear pair)MGH+85°=180°

EGH=85°(corresponding angles)MGH+EGH= 180°(Linear pair)MGH+85°=180°MGH=180°-85°

EGH=85°(corresponding angles)MGH+EGH= 180°(Linear pair)MGH+85°=180°MGH=180°-85°MGH=95°

  • EGH=85°(corresponding angles)MGH+EGH= 180°(Linear pair)MGH+85°=180°MGH=180°-85°MGH=95°MGH+x=115°(exterior angle property)

EGH=85°(corresponding angles)MGH+EGH= 180°(Linear pair)MGH+85°=180°MGH=180°-85°MGH=95°MGH+x=115°(exterior angle property)95°+x=115°

EGH=85°(corresponding angles)MGH+EGH= 180°(Linear pair)MGH+85°=180°MGH=180°-85°MGH=95°MGH+x=115°(exterior angle property)95°+x=115°x=115-95°

EGH=85°(corresponding angles)MGH+EGH= 180°(Linear pair)MGH+85°=180°MGH=180°-85°MGH=95°MGH+x=115°(exterior angle property)95°+x=115°x=115-95°x=20°

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