Question

In the fig. AB ||DE AND BC ||EF . PROVE THAT AC||DF ​

Answer 1

Answer:

Prove it using the congurency of triangle.

It can be done as follows:-

As AB//DE and BC//EF

==> angle ABC = angle DEF.

Therefore in triangle

ABC and DEF.

AB//DE

BC//EF and

angle ABC = angle DEF

So, both the traingles are Congurent.

Now, By CPCT(Class 9)

AC// DF.

It will be more helpful for others and me if u mark

Answer 2

Step-by-step explanation:

In triangle AOC and DOF

AB parallel to DE

AO/DO = BO/OE (1)

by thels thm.

InTriangle AOC and DOF

BC parallel to EF

CO/FO =BO/OE. (2)

from 1 and 2

AO/DO=CO/FO

BY Converse of thels thom.

AC parallel to DF