Question

In the fig. AB is a chord &
"O' is centre of circle
If OM 1 AB & OM = 3.
5
3
OA = = 5
A
B
find the length of chord AB.​

Answer 1

Answer:

$given \: \\ oa \: = - 5cm \\ om = 3cm \\ \\ angle \: = {90}^{.}$

${am}^{2} = {oa}^{2} - {om}^{2}$

$= ( { - 5}^{2} ) - ( {3}^{2} )$

$= 25 - 9$

$= 4 \: cm$

$w e \: know \: that \: perpendicular \: from \: centre \: bisects \: cord \:$

$therefore \: ab \: = 2 \: am$

$ab \: = 8 \: cm$