Question

in the fig ,Ab is a mirror PQ is the incident Ray and QR the reflected Ray .if angle PQR =120° ,find angle PQA​

Answer 1

Answer:

As we know that,

angle of incidence = angle of reflection

(Law of reflection)

⇒ ZP QA = ZRQB

Now,

ZP QA + ZP QR + ZRQB = 180°

⇒ ZPQA + ZPQA + 112° =

180° (ZP QA = ZRQB)

⇒ 2/PQA = 180° - 112°

=>∆PQR =

$\frac{68}{2}$

=34°